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x^2+2.55x-4.5=0
a = 1; b = 2.55; c = -4.5;
Δ = b2-4ac
Δ = 2.552-4·1·(-4.5)
Δ = 24.5025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.55)-\sqrt{24.5025}}{2*1}=\frac{-2.55-\sqrt{24.5025}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.55)+\sqrt{24.5025}}{2*1}=\frac{-2.55+\sqrt{24.5025}}{2} $
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